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# Python program to check if the number provided by the user is an Armstrong number or not
# take input from the user
num = int(input("Enter a number: "))
# initialise sum
sum = 0
# find the sum of the cube of each digit
temp = num
while temp > 0:
digit = temp % 10
sum += digit ** 3
temp //= 10
# display the result
if num == sum:
print(num,"is an Armstrong number")
else:
print(num,"is not an Armstrong number")
Output 1Enter a number: 663 663 is not an Armstrong numberOutput 2
Enter a number: 407 407 is an Armstrong numberHere, we ask the user for a number and check if it is an Armstrong number. We need to calculate the sum of cube of each digit. So, we initialize the sum to 0 and obtain each digit number by using the modulus operator %. Remainder of a number when it is divide by 10 is the last digit of that number. We take the cubes using exponent operator. Finally, we compare the sum with the original number and conclude that it is Armstrong number if they are equal.
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